给定一个二维数组matrixatrix,一个人必须从左上角出发,最后到达右下角,沿途只可以向下或向右走,沿途数字的都累加就是距离的累加和。求最小的距离累加和。
DP
public static int minPathSum1(int[][] matrix) {
if (matrix == null || matrix.length == 0 || matrix[0] == null || matrix[0].length == 0) {
return 0;
}
int row = matrix.length;
int col = matrix[0].length;
int[][] dp = new int[row][col];
dp[0][0] = matrix[0][0];
for (int i = 1; i < row; i++)
dp[i][0] = dp[i - 1][0] + matrix[i][0];
for (int j = 1; j < col; j++)
dp[0][j] = dp[0][j - 1] + matrix[0][j];
for (int i = 1; i < row; i++) {
for (int j = 1; j < col; j++) {
dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + matrix[i][j];
}
}
return dp[row - 1][col - 1];
}
DP(空间压缩优化)
public static int dp(int[][] matrix) {
if (matrix == null || matrix.length == 0 || matrix[0] == null || matrix[0].length == 0) {
return 0;
}
int row = matrix.length;
int col = matrix[0].length;
int[] arr = new int[col];
arr[0] = matrix[0][0];
for (int j = 1; j < col; j++) {
arr[j] = arr[j - 1] + matrix[0][j];
}
for (int i = 1; i < row; i++) {
arr[0] += matrix[i][0];
for (int j = 1; j < col; j++) {
arr[j] = Math.min(arr[j - 1], arr[j]) + matrix[i][j];
}
}
return arr[col - 1];
}